I have a problem here involving natural logs, please show your work so I can learn if I'm making a mistake.
Simplify the following expression as completely as possible:
5x + ln (3x) - ln (9x^2) + ln (3) - ln (x) + ln (x^2) -4x
I know I can put the 2 exponential numbers in front of their natural logs ex. 2 ln (9x), 2 ln (x), but I'm having trouble deciding where to divide/multiply/etc.
so going off ln(3x) - ln(x) and ln(x^2) - ln (9x^2) the answer would come out as ln(3) - ln(9), then I could add the former ln(3) and x to get
2 ln(3) - ln(9) + x which would cancel out to x?
Man, if that's right I'm going to be so glad I asked you guys. *hopes*