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Math Help - Help Graphing y=3cot(x+pi/2)

  1. #1
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    Help Graphing y=3cot(x+pi/2)

    y=3cot(x+pi/2)
    set up inequality:
    0<x+pi/2<pi/2 = -pi/2<x<0

    asymptotes = -pi/2 and 0
    x-intercept of graph/line = (-pi/2+0)/2=-pi/4

    so it's -pi/4 but the back of the book says its at 0 for the first period of where the line intercept at the x-axis!? i'm so confused, i don't see my errors.
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  2. #2
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    Post the text of the complete problem.
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  3. #3
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    graph two periods of the given cotangent function.

    Please someone help me i am really getting frustrated over this, it's giving me a headache.
    Last edited by Frenchie; August 3rd 2010 at 08:09 PM.
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  4. #4
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    EDIT: Sorry my mistake, after 4 hours i finally figured out what the problem was, i was setting up the inequality as 0<x+pi/2<pi/2 which should actually be 0<x+pi/2<pi
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  5. #5
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    To find x intercept of the graph put y = 0.
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