I know the answer is (0,2) U (2, infinity)

f(x) =squareroot(4x-3)

(x^2)-4

Do you set the denominator to zero? I am not 100% sure.

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- Jul 29th 2010, 09:05 PMdanielh9103Finding Domain without a calculator
I know the answer is (0,2) U (2, infinity)

f(x) =__squareroot(4x-3)__

(x^2)-4

Do you set the denominator to zero? I am not 100% sure. - Jul 29th 2010, 09:11 PMundefined
$\displaystyle \displaystyle f(x) = \frac{\sqrt{4x-3}}{x^2-4}$

Are you sure it's not $\displaystyle \displaystyle \left[\frac{3}{4},2\right)\cup (2,\infty)$?

You are on the right track; set the denominator to zero because when it is zero, f is undefined (so exclude any such x from the domain). Also, solve $\displaystyle 4x-3<0$ because that will make $\displaystyle \sqrt{4x-3}$ non-real. - Jul 29th 2010, 09:14 PMpickslides
You are on the right track $\displaystyle x^2-4\neq 0$ and $\displaystyle 4x-3>0$