Help:

$\displaystyle 7^-^4^x = 2^1^+^3^x$

I should take the ln of both sides, right...?

$\displaystyle -4x ln 7 = (1+3x) ln 2$

How do I simplify?

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- Jul 29th 2010, 12:36 PMjimmy1X in exponent on both sides, can't make bases the same
Help:

$\displaystyle 7^-^4^x = 2^1^+^3^x$

I should take the ln of both sides, right...?

$\displaystyle -4x ln 7 = (1+3x) ln 2$

How do I simplify? - Jul 29th 2010, 12:43 PMAckbeet
I would distribute out the RHS first. Your goal, as always is to get the terms with x's on one side, and all the other terms on the other.

- Jul 29th 2010, 12:43 PMbobak
You don't want to simplify, you want to solve the equation. Step back and look at what you have written, remember that ln7 and ln2 are just numbers.

- Jul 29th 2010, 12:48 PMeumyang