Could somebody point me in the right direction?

$\displaystyle e^x + e^-^x = 2$

$\displaystyle e^x (e^x + e^-^x) = 2*e^x$

$\displaystyle e^2x + e = 2e^x$

$\displaystyle e^2x - 2e^x + e = 0$

Something tells me I should be able to solve this as a quadratic, but e is a constant, and I can't figure out how to do this with a constant as the base.