# Math Help - Find the domain range and inverse

1. ## Find the domain range and inverse

f(x)=arcsin(sqrt(x))

i think the domain is x>=1
inverse is sin(sqrt(x))
not sure about the range can someone help

2. I think $x \in [0,1]$

and $f^{-1}= \sin^2{x}$

Now I have given you the domain, what do you think the range could be?

3. [0,pi/2]

4. Yep.

5. how did you come up with the domain

6. I asked myself 3 questions, what is the domain of $\sqrt{x}$ ? what is the domain of $\arcsin{x}$ and what is there intersection?