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Math Help - Find the domain range and inverse

  1. #1
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    Find the domain range and inverse

    f(x)=arcsin(sqrt(x))

    i think the domain is x>=1
    inverse is sin(sqrt(x))
    not sure about the range can someone help
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  2. #2
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    I think x \in [0,1]

    and f^{-1}= \sin^2{x}

    Now I have given you the domain, what do you think the range could be?
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  3. #3
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    [0,pi/2]
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  4. #4
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    Yep.
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  5. #5
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    how did you come up with the domain
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  6. #6
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    I asked myself 3 questions, what is the domain of \sqrt{x} ? what is the domain of \arcsin{x} and what is there intersection?
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