f(x)=arcsin(sqrt(x))

i think the domain is x>=1

inverse is sin(sqrt(x))

not sure about the range can someone help

Printable View

- Jul 28th 2010, 02:58 PMdat1611Find the domain range and inverse
f(x)=arcsin(sqrt(x))

i think the domain is x>=1

inverse is sin(sqrt(x))

not sure about the range can someone help - Jul 28th 2010, 03:13 PMpickslides
I think

and

Now I have given you the domain, what do you think the range could be? - Jul 28th 2010, 03:34 PMdat1611
[0,pi/2]

- Jul 28th 2010, 04:30 PMpickslides
Yep.

- Jul 28th 2010, 04:38 PMdat1611
how did you come up with the domain

- Jul 28th 2010, 04:47 PMpickslides
I asked myself 3 questions, what is the domain of ? what is the domain of and what is there intersection?