# Find the domain range and inverse

• Jul 28th 2010, 01:58 PM
dat1611
Find the domain range and inverse
f(x)=arcsin(sqrt(x))

i think the domain is x>=1
inverse is sin(sqrt(x))
not sure about the range can someone help
• Jul 28th 2010, 02:13 PM
pickslides
I think $x \in [0,1]$

and $f^{-1}= \sin^2{x}$

Now I have given you the domain, what do you think the range could be?
• Jul 28th 2010, 02:34 PM
dat1611
[0,pi/2]
• Jul 28th 2010, 03:30 PM
pickslides
Yep.
• Jul 28th 2010, 03:38 PM
dat1611
how did you come up with the domain
• Jul 28th 2010, 03:47 PM
pickslides
I asked myself 3 questions, what is the domain of $\sqrt{x}$ ? what is the domain of $\arcsin{x}$ and what is there intersection?