Q1. Solve equa for z=a+bi where a and b are real numbers. (z-zbar)^2=2z+6i The ans is -18-3i but do not know how they get this.
Last edited by heatly; July 27th 2010 at 04:17 PM.
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for is Now expand this expression out.
Thanks for that ,But i did that and and got -2b^2=a+bi+3i The ans is supposed to be -18-3i
I get Now equating coefficients
Thanks for that. I have another one Iam having difficulty with too iff your interested. z^2 = 3i
Can you solve it form here?
. So or .
'pickslides' Thats actually where I got up to and then I got stuck in finding a and b. if you can go a bit futher would be good.
Thanks,the ans in my text book says..... +-sqrt(3/2)*(1+i)
Originally Posted by pickslides Actually ...
Originally Posted by heatly Thanks,the ans in my text book says..... +-sqrt(3/2)*(1+i) Which is the same as what I put, I however have rationalised the denominator.
Thanks Prove It
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