Hey everybody, I have this inequality that I was wondering if I did right, so if anybody can verify for me please?

a) $\displaystyle \frac{3x-9}{x^2-1}\leq -1$

I got $\displaystyle (-\infty, -1)\bigcup(1,3)$ again if anybody can verify this?

Never mind I caught a mistake I forgot to get all the numbers to one side and make the inequality equal 0