can someone please help me with this verbal problem? (Worried)

The sum of 3 consecutive integers is 75 less than 5 times the smallest integer. Find the LARGEST of the integers.

thx

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- Jul 26th 2010, 07:04 PMcristinaivelisseVerbal Problem
can someone please help me with this verbal problem? (Worried)

The sum of 3 consecutive integers is 75 less than 5 times the smallest integer. Find the LARGEST of the integers.

thx - Jul 26th 2010, 07:14 PMeumyang
$\displaystyle n + (n + 1) + (n + 2) = 5n - 75$

Solve for n; the largest integer would be n + 2. - Jul 26th 2010, 07:16 PMbondesan
Let a, b, c be three consecutive integers with a < b < c. So we have:

The sum of 3 consecutive integers: a + b + c

(Is) 75 less than 5 times the smallest integer: 5a - 75

So we have: a + b + c = 5a - 75.

If a, b and c are consecutives, and as we choose "a" as the smallest integer, then b = a+1 and c = a+2.

Thus: a + b + c = 5a - 75 => a + (a+1) + (a+2) = 5a - 75

3a + 3 = 5a - 75

-2a = -78

a = 39

The largest integer is c, wich is a + 2, so c = 41. - Jul 26th 2010, 07:20 PMeumyang
- Jul 26th 2010, 07:28 PMbondesan