[x - 7x(squaeroot(x))] / squaeroot(x)
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$\displaystyle \frac{x-7x\sqrt{x}}{\sqrt{x}}= \frac{x}{\sqrt{x}}-\frac{7x\sqrt{x}}{\sqrt{x}}= \frac{x}{\sqrt{x}}-7x$ Use index laws on the first term to finish.