[x - 7x(squaeroot(x))] / squaeroot(x)

Printable View

- Jul 11th 2010, 04:01 PMsuperduper1Simplify
[x - 7x(squaeroot(x))] / squaeroot(x)

- Jul 11th 2010, 04:12 PMpickslides
$\displaystyle \frac{x-7x\sqrt{x}}{\sqrt{x}}= \frac{x}{\sqrt{x}}-\frac{7x\sqrt{x}}{\sqrt{x}}= \frac{x}{\sqrt{x}}-7x$

Use index laws on the first term to finish.