ok so i need to find the intercepts, includes x and y, of this equation y=(x-1) times the square root of (x^2+1)
so far when i try doing it i don't get the points which are shown in the calculator
To find the y-intercept, set x=0.
$\displaystyle y=(0-1)\sqrt{0^2+1} = -1$
The y-intercept is at point (0,-1).
To find the x-intercept, set y=0.
$\displaystyle 0=(x-1)\sqrt{x^2+1}$
Since $\displaystyle \displaystyle\sqrt{x^2+1}$ can't equal 0, we must have x = 1.
The x-intercept is at point (1,0).