ok so i need to find the intercepts, includes x and y, of this equation y=(x-1) times the square root of (x^2+1)

so far when i try doing it i don't get the points which are shown in the calculator

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- Jul 7th 2010, 08:42 AMla_lo626Finding intercepts
ok so i need to find the intercepts, includes x and y, of this equation y=(x-1) times the square root of (x^2+1)

so far when i try doing it i don't get the points which are shown in the calculator - Jul 7th 2010, 08:47 AMundefined
To find the y-intercept, set x=0.

$\displaystyle y=(0-1)\sqrt{0^2+1} = -1$

The y-intercept is at point (0,-1).

To find the x-intercept, set y=0.

$\displaystyle 0=(x-1)\sqrt{x^2+1}$

Since $\displaystyle \displaystyle\sqrt{x^2+1}$ can't equal 0, we must have x = 1.

The x-intercept is at point (1,0). - Jul 7th 2010, 08:57 AMla_lo626
- Jul 7th 2010, 09:05 AMundefined
- Jul 7th 2010, 09:12 AMla_lo626
thanks "undefined" i see now sort of it's a little more clear