I'm having problems with this maths question:

Graph y=-ln|x+2| +3.

I don't understand why even tho +3 is at the back, the graph moved down 3 units instead of up? Does reflection in x-axis come AFTER translations?

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- July 6th 2010, 06:45 AMLushoramaGraphing y=-ln|x+2| +3.
**I'm having problems with this maths question:**

**Graph y=-ln|x+2| +3.**

**I don't understand why even tho +3 is at the back, the graph moved down 3 units instead of up? Does reflection in x-axis come AFTER translations?** - July 6th 2010, 06:55 AMmr fantastic
- July 6th 2010, 07:46 AMHallsofIvy
However, whether you do it as y= -(ln|x+2|- 3) or y= -ln|x+2|+ 3, the graph is 3 places

**higher**than the graph of y= -3ln|x+2|, not lower!

For example, for x= -1, ln|-1+2|= ln|1|= 0 so y= -(0- 3)= 3 while -ln|x+2|+ 3= -ln|1|+ 3= 3. The graph y= -ln(x+2) passes through the point (-1, 0) while the graph of y= -ln|x+2|+ 3 passes through the point (-1, 3), three places higher.

If your problem is actually y= -(ln|x+2|+ 3)= -ln|x+2|- 3,**then**the graph passes through (-1, -3), three places lower.