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Math Help - A Graph Problem :?

  1. #1
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    Exclamation A Graph Problem :?

    Graph the line x+y= 5 on the graph provided. Then graph the results.

    x|y
    5|0
    0|?
    ?|?

    Graph the line x-y=1 on the graph.

    x|y
    ?|?
    ?|?
    ?|?

    What is the point of intersection of the two lines?
    What is the slope of line y=3/4x-1?
    What is the y-intercept of line 2x+3y=6?

    Find an equation of the line with slope -4/3 and y-intercept 3. Leave equation in slope-intercept form.

    Find an equation of the line that goes thru the point (2,1) and has a slope of 4. Leave equation in point-slope form.

    I know it's a lot but I really need a lot of help. Thank you in advance!
    Attached Thumbnails Attached Thumbnails A Graph Problem :?-plain-graph.gif  
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  2. #2
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    x+y= 5
    change this so it becomes y = 5 -x
    This way, u can choose any x value and subtitute it in to get y.
    ie. x = 0
    y = 5 - 0
    y = 5
    Point (0, 5)
    Choose at least 3 other points to draw the line.


    x-y=1
    Do the same.
    y = x -1
    Choose at least 3 other points to draw the line.


    What is the point of intersection of the two lines?
    In the graph I made the dots red, where the lines intersects x and y axes.

    What is the slope of line y=3/4x-1?
    This is in the form of y = mx + c
    m is the slope so slope = 3/4

    What is the y-intercept of line 2x+3y=6?
    Y intercept is when x = 0
    Substitute this in and you get: 2*0 + 3y = 6
    3y = 6
    y = 2
    Y-intercept = (0, 2)

    Find an equation of the line with slope -4/3 and y-intercept 3. Leave equation in slope-intercept form.
    I don't know if this is what they are looking for.
    3 = -4/3x + c
    Y - Int. x = 0
    y = -4/3 + 3

    Find an equation of the line that goes thru the point (2,1) and has a slope of 4. Leave equation in point-slope form.
    I don't know if this is what they are looking for.
    1 = 4x + c
    1 = 8 + c
    c = -7
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  3. #3
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    Thumbs up

    Thank you so much for all your help! It is much appreciated! Can I ask you..how do I figure out how to fill out the input/output table? And i'm afraid the last two questions aren't what they are looking for but I sooo appreciate all your help! Thanks a mil!
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  4. #4
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    Quote Originally Posted by IHATECHONGAS View Post
    Can I ask you..how do I figure out how to fill out the input/output table?
    x+y= 5
    change this so it becomes y = 5 -x

    In your table:
    x|y
    5|0
    0|?
    ?|?

    You have the x value. Subtitute this into
    y = 5 -x

    y = 5 - 5 = 0
    y = 5 - 0 = 5
    y = 5 - ? = (in this table, the x's are going down in 5s so the next value should be -5.)
    y = 5 - (-5) = 10
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  5. #5
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    Post

    Sooo..on this table it would be backwards???

    Graph the line x-y=1 on the graph.

    x|y
    ?|?
    ?|?
    ?|?
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  6. #6
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    Quote Originally Posted by r_maths View Post
    x+y= 5
    x-y=1
    Do the same.
    y = x -1
    Choose at least 3 other points to draw the line.
    Make up 3 x points and substitute into equation y = x -1
    For example. if you look at the line I drew for you.
    When x = 0 y = -1 hence the point (0, -1)
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