Natural Logs help

**orkdork** · July 4th 2010, 02:08 PM

$ln (e^{x^2-y^2})$

Anyone able to help me?

**pickslides** · July 4th 2010, 02:11 PM

Follow this.

$\log_ab^c = c\log_ab$

**Also sprach Zarathustra** · July 4th 2010, 02:11 PM

Use this formula:

$ln (a)^b=b \cdot ln(a)$

**HallsofIvy** · July 6th 2010, 01:09 AM

Another way to do basically what pickslides and Also sprach Zarathustra suggest is to use the fact that ln(x) and $e^x$ are inverse functions: $ln(e^x)= x$ .

**mr fantastic** · July 6th 2010, 07:12 AM

Originally Posted by orkdork

$ln (e^{x^2-y^2})$

Anyone able to help me?

If you say what you're meant to be doing with this expression, then the answer to "anyone able to help me?" might be yes.

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