Help me. Please check if I did the domain range and graph right. Thanks. 1. 2.
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Originally Posted by reiward Help me. Please check if I did the domain range and graph right. Thanks. 1. 2. 1. Everything is correct except your graph. 2. The range is $\displaystyle \mathbf{R}\backslash \{6 \}$.
Originally Posted by Prove It 1. Everything is correct except your graph. 2. The range is $\displaystyle \mathbf{R}\backslash \{6 \}$. 1. Could you show me how to graph it. Thanks. 2. Oh, does that mean my graph is also wrong?
Originally Posted by reiward 1. Could you show me how to graph it. Thanks. 2. Oh, does that mean my graph is also wrong? 1. The line should end at $\displaystyle x = 1$ with a QUADRATIC graph starting at $\displaystyle x = 1$. 2. The graph is almost right, you just need a hole at $\displaystyle (3, 6)$ on the line.
Originally Posted by Prove It 1. The line should end at $\displaystyle x = 1$ with a QUADRATIC graph starting at $\displaystyle x = 1$. 2. The graph is almost right, you just need a hole at $\displaystyle (3, 6)$ on the line. 1. Sorry to bother but can you draw it? I cant seem to picture it out. Im really not good at this sorry. 2. I get it. Ty! Oh. Is the range = [6] or not equal to 6?
Last edited by reiward; Jul 1st 2010 at 04:21 AM.
Originally Posted by reiward 1. Sorry to bother but can you draw it? I cant seem to picture it out. Im really not good at this sorry. 2. I get it. Ty! Oh. Is the range = [6] or not equal to 6? $\displaystyle \mathbf{R}\backslash \{6\}$ means all the real numbers except 6. For the graph, draw the graph of $\displaystyle y = x^2$. Then get rid of everything to the left of $\displaystyle x = 1$.
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