given triangle ABC.....
The question is:
Given the triangle ABC with AB=5 and BC= 5sqrt3/3
The measure of the angle A is 30 degrees. How many choices are there for the measure of angle C?
I've hit a problem with the final solution.
multiply both sides by 5
since Im dealing with sin, I reference the unit circle and see that sin is sqrt3/2 at pi/3 and 2pi/3.
That means I have 2 choices for angle C?
As long as the two angles aren't greater than 180, you should be fine since all 3 angles need to equal 180.
Originally Posted by ninobrn99