Math Help - Evaluate the difference quotient for the function f(x) = 2 - 2x - X^2

1. Evaluate the difference quotient for the function f(x) = 2 - 2x - X^2

Consider the function: f(x) = 2 - 2x - X^2

Evaluate the difference quotient for the given function. Simplify your answer.
f(2+h) - f(2) / h

I found f(2+h) = (-6 -6h -h^2)
I found f(2) = (-22)

Can this be simplified any more?
Please show me how.
-h^2 -6h +16 / h

2. I don't know why you've evaluated the function at $x = 2$...

It should be

$\frac{f(x + h) - f(x)}{h}$...

3. Originally Posted by superduper1
Consider the function: f(x) = 2 - 2x - X^2

Evaluate the difference quotient for the given function. Simplify your answer.
f(2+h) - f(2) / h

I found f(2+h) = (-6 -6h -h^2)
I found f(2) = (-22)

Can this be simplified any more?
Please show me how.
-h^2 -6h +16 / h
$f(2+h) = 2 - 2(2+h) - (2+h)^2$

$f(2+h) = 2 - 4 - 2h - (4 + 4h + h^2)$

$f(2+h) = -6 - 6h - h^2$

$f(2) = 2 - 2(2) - 2^2 = -6$

try again