Thread: complex algebra

Can \alpha=\beta ?I thought its stated clearly that

\alpha<-1<\beta

No, they're not equal at all. The only thing we change is 'what' we call

We call the roots, with

We simply call , the smallest of the 2 roots, and the other. Thus if the inequality '<' flips into '>' due to a negative sign, then we only change what we call . Perhaps, I was unclear.

I hope you understand what I mean, now.

Originally Posted by Dinkydoe

No, they're not equal at all. The only thing we change is 'what' we call

We call the roots, with

We simply call , the smallest of the 2 roots, and the other. Thus if the inequality '<' flips into '>' due to a negative sign, then we only change what we call . Perhaps, I was unclear.

I hope you understand what I mean, now.

yeah, they are unknowns anyways. No worries Dinky, you've been very helpful and precise in explaining. thanks !

Originally Posted by hooke

yeah, they are unknowns anyways. No worries Dinky, you've been very helpful and precise in explaining. thanks !

I would like to do a final checking, is the answer -1<m<4 ?

I found something slightly different.

I guess that you also found that



could be simplified to

This polynomial can be factored:

. Thus we find zero's

Then we can argue that, (or see by plotting) that as or

it is very easy,but your thinking is worry. wow gold