If f(x) = 2x^2-x +4 Find 2f(a) How do I deal with the 2 in front of the f(a) ? Typically I just plug 'a' into the values of x and compute. But how do I deal with the 2?
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Originally Posted by superduper1 If f(x) = 2x^2-x +4 Find 2f(a) How do I deal with the 2 in front of the f(a) ? Typically I just plug 'a' into the values of x and compute. But how do I deal with the 2? $\displaystyle 2 f(a) = 2(2a^2-a +4) = .... $
2f(a) = 4a^2 - 2a + 8 ?
Originally Posted by superduper1 2f(a) = 4a^2 - 2a + 8 ? yes, just multiply f(a) by 2.