Um, how would one convert this rectangular equation into polar form:

(x+1)^2 + (y-4)^2 = 17

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- Jun 23rd 2010, 10:09 PMNotoriousPiPolar Coordinates Question (Solved)
Um, how would one convert this rectangular equation into polar form:

(x+1)^2 + (y-4)^2 = 17 - Jun 23rd 2010, 11:16 PMred_dog
Put $\displaystyle x=\rho\cos\theta, \ y=\rho\sin\theta$. Then

$\displaystyle (\rho\cos\theta+1)^2+(\rho\sin\theta-4)^2=17$

$\displaystyle \rho^2(\cos^2\theta+\sin^2\theta)+2\rho\cos\theta-8\rho\sin\theta=0$

$\displaystyle \rho^2+2\rho(\cos\theta-4\sin\theta)=0$ - Jun 23rd 2010, 11:26 PMNotoriousPi
Many thanks. I solved this problem differently, but I was checking to match up answers.

- Jun 24th 2010, 01:07 PMHallsofIvy
Then you should have given the answer first and asked others to check it. Many people will not simply give you the answer to a home work problem.

- Jun 24th 2010, 05:47 PMNotoriousPi
Well, it was actually to study before a test, but yes, if I do have similar problems, I will post up next time.