3(2^(x+1)) + 2(5^(x-2)) = 5^x + 2^(x-2)
I know I'm supposed to move the base 2s and base 5s to one side and factor out 2^x and 5^x, but I have no idea how to do it. Any help?
3(2^(x+1)) + 2(5^(x-2)) = 5^x + 2^(x-2)
I know I'm supposed to move the base 2s and base 5s to one side and factor out 2^x and 5^x, but I have no idea how to do it. Any help?
rearranging we get
Now the laws of exponents tell us that so
(Note: It will almost always be easier to express in terms of the lowest power, in this case (x-2) for both exponents 2,5).
Now factorise and then take the log of both sides. Use your log laws to solve for x.
No. We get
which is used correctly belowNow the laws of exponents tell us that so
(Note: It will almost always be easier to express in terms of the lowest power, in this case (x-2) for both exponents 2,5).
Now factorise and then take the log of both sides. Use your log laws to solve for x.