The question starts as

I've gotten this far and don't know how to solve the rest.

Substitute

Then I don't know how to solve the rest, when I substitute an x, I get a zero for both, it's completely different from this.

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- Jun 9th 2010, 04:28 AMCthulAnother type of Partial Fractions
The question starts as

I've gotten this far and don't know how to solve the rest.

Substitute

Then I don't know how to solve the rest, when I substitute an x, I get a zero for both, it's completely different from this. - Jun 9th 2010, 06:15 AMArchie Meade
- Jun 10th 2010, 01:23 AMCthul
It won't work, it doesn't when I sub in zero, I get 2 variables.

- Jun 10th 2010, 01:32 AMProve It
- Jun 10th 2010, 02:56 AMArchie Meade
- Jun 10th 2010, 04:05 AMCthul
I thought when x is substituted with zero, you'd get... which makes .... oh, I see. Thanks. The signs get confusing.

- Jun 10th 2010, 06:12 AMArchie Meade
Thinking of subtracting negative numbers as the difference between temperatures can be helpful...

5-2 is the difference between 5 and 2 degrees, which is 3 degrees.

There is a 6 degree difference between between 5 and -1,

5 degrees down to zero and another degree down to -1.

That's a drop of 6 degrees.

So 5-(-1) is that difference which we know is 6,

subtracting the lower temperature from the bigger one.

Since 5+1=6, we can say 5--1=5+1,

so 1--1=1+1 and so on...

-2-3 is subtract 2, then subtract 3, which is subtract 5 or -(2+3)

-2--3=-2-(-3), the difference between -2 degrees and -3 degrees which is 1 degree

as -2 is greater than -3,

so -2--3=1=3-2 or -2+3 etc - Jun 10th 2010, 01:09 PMCirculation
Partial fractions appear to be a very interesting problem.