1. ## Help Partial Fractions

$\frac{1+x}{x(1+x^{2})}$

When I expand this, I can't eliminate to get one variable to get the variable.

2. Originally Posted by Cthul
$\frac{1+x}{x(1+x^{2})}$

When I expand this, I can't eliminate to get one variable to get the variable.
Write it as

$\frac{A}{x} + \frac{Bx + C}{1 + x^2} = \frac{1 + x}{x(1 + x^2)}$

$\frac{A(1 + x^2) + (Bx + C)x}{x(1 + x^2)} = \frac{1 + x}{x(1 + x^2)}$

$A(1 + x^2) + (Bx + C)x = 1 + x$

$A + Ax^2 + Bx^2 + Cx = 1 + x$

$(A + B)x^2 + Cx + A = 0x^2 + x + 1$.

Equating coefficients of like powers of $x$ gives

$A + B = 0, C = 1, A = 1$.

So $B = -1$.

Therefore:

$\frac{1}{x} + \frac{1 - x}{1 + x^2} = \frac{1 + x}{x(1 + x^2)}$.

3. Thank you, problem solved. I understand how now.