Solve $\displaystyle \log_{3}(2x-1)=2$
Last edited by mr fantastic; Jun 9th 2010 at 12:28 AM. Reason: Re-titled and edited (I have assumed the OP wants to solve the equation).
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Originally Posted by Stud778 $\displaystyle \log_{3}(2x-1)=2$ $\displaystyle \frac{log(2x-1)}{log(3)}=2$ $\displaystyle log(2x-1) = 2log(3)$ $\displaystyle log(2x-1) = log(3^2)$ can you finish?
Originally Posted by Stud778 $\displaystyle \log_{3}(2x-1)=2$ property of log 3^2=2x-1 9=2x-1 10=2x x=5
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