Find the focus, directrix and axis of the parabola with equation x= 2y^2+3? x-3= 2y^2 x-3 = y^2 -------------> Is it how you solve it? Thank you for helping me!
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Originally Posted by htk Find the focus, directrix and axis of the parabola with equation x= 2y^2+3? x-3= 2y^2 x-3 = y^2 -------------> Is it how you solve it? Thank you for helping me! 1. This is a parabola opening to the right. The general equation of such a parabola is: where V(k, h) is the vertex, F(k+p, h) is the focus and d: x = k-p is the equation of the directrix. 2. Transform the given equation into the general form: 3. Determine V, F and d.
Last edited by earboth; June 9th 2010 at 02:55 AM. Reason: typo detected
So, V (3,0) F=(25/8, 0) D x= 23/8 Are these correct? Thanks again! 4p= 1/2 p= 1/8
Originally Posted by htk So, V (3,0) F=(25/8, 0) D x= 23/8 Are these correct? Thanks again! 4p= 1/2 p= 1/8 Perfect!
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