Find the focus, directrix and axis of the parabola with equation x= 2y^2+3?
x-3= 2y^2
x-3 = y^2 -------------> Is it how you solve it?
Thank you for helping me!
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Find the focus, directrix and axis of the parabola with equation x= 2y^2+3?
x-3= 2y^2
x-3 = y^2 -------------> Is it how you solve it?
Thank you for helping me!
1. This is a parabola opening to the right. The general equation of such a parabola is:Quote:
Originally Posted by htk
where V(k, h) is the vertex, F(k+p, h) is the focus and d: x = k-p is the equation of the directrix.
2. Transform the given equation into the general form:
3. Determine V, F and d.
So, V (3,0) F=(25/8, 0) D x= 23/8 Are these correct? Thanks again!
4p= 1/2
p= 1/8
Perfect! (Clapping)Quote:
Originally Posted by htk