ln(x)=e^(-x)

find x... :(

Printable View

- Jun 8th 2010, 11:46 AMice_syncerln(x)=e^-x find x
ln(x)=e^(-x)

find x... :( - Jun 8th 2010, 01:39 PMArchie Meade
- Jun 8th 2010, 08:35 PMmr fantastic
- Jun 9th 2010, 04:11 AMice_syncer
how did you think of the initial shot ie x = 1.6

- Jun 9th 2010, 05:56 AMArchie Meade
is a decreasing function, while is increasing.

Hence these cross between x=1 and x=2.

You could choose any value of x in the vicinity as a starting point, say x=1.5 or so. Choosing x=1 or x=2 would also suffice.

The attachment shows Newton's method homing in on the solution. - Jun 9th 2010, 11:37 AMice_syncer
.......ok... I'll read more about it, thanks!