# Thread: Equation of a half circle

1. ## Equation of a half circle

Find an expression for the for the function whose graph is the given curve. Give the domain and range.

The bottom half of the circle whose center is @(3,0) and has a radius of length 5.

I'm so lost.

2. Here is the equation of the whole circle.

$(x-3)^2+y^2=5^2$

Now find y1 and y2, the negative square root would be the botom half of the circle.

Regards.

3. Lets find the equation of the full circle first.

This is $y^2 + (x-3)^2 = 5^2$

Rearrange for Y

This is $y = \sqrt{25 - (x-3)^2}$

When it is in this form, the range and domain are defined as follows:
The domain is all possible values that x can take
The range is all possible values that y can take

Because it is a circle with radius 5, centered around (3,0); you know the domain and range are:
Domain: $-2 \leq x \leq 8$
Range: $-5 \leq y \leq 5$

You want the bottom half of the circle, which is the part where Y<0.
Hopefully, you can see that
Domain: $-2 \leq x \leq 8$ (the same)
Range: $-5 \leq y \leq 0$ (bottom half only)

This is much easier to draw than do in your head. I'll try to attach an image later

edit too slow

4. I got the same answer as SpringFan25.