Hi, I'll be grateful if you could help with this problem.
The tangents of the parabola x2 - mx + 3/2 intersect perpendicularly at the origin, then what is the positive value of m?
Thanks in advance.
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The equation of the tangent at the point whose abscissa is "a" is
y = (2a-m)x-a²+3/2
The tangent passes through the origin when
-a²+3/2 = 0
This gives 2 values : a1=sqrt(3/2) and a2=-sqrt(3/2) Spoiler: The two tangent intersect perpendicularly when
Thank you! You helped a lot!
Last edited by truevein; Jun 6th 2010 at 02:00 PM.
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