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Math Help - Finding a limit.

  1. #1
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    Finding a limit.

    \lim_{x \to 0} \frac{(1+x)^{1/3} (\sqrt{4+x} -1) - \sqrt{1-x}}{4 x}
    Last edited by mr fantastic; June 9th 2010 at 09:29 PM. Reason: Fixed latex, re-titled.
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  2. #2
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    Quote Originally Posted by bgbgbgbg View Post
    lim_(x->0) ((1+x)^(1/3) (sqrt(4+x)-1)-sqrt(1-x))/(4 x)
    is this what you mean?

    \lim_{x \to 0} \frac{(1+x)^{\frac{1}{3}}  [(\sqrt{4+x}-1)-\sqrt{1-x}]}{4x}
    Last edited by skeeter; June 6th 2010 at 05:45 AM.
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  3. #3
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    Hello, bgbgbgbg!

    I think you meant: . \lim_{x\to0} \frac{(1+x)^{1/3} (\sqrt{4+x}-1)-\sqrt{1-x}}{4x}

    . . But it doesn't matter . . .


    Plug in x = 0 and see what you get.

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