Finding a limit.

• June 6th 2010, 04:59 AM
bgbgbgbg
Finding a limit.
$\lim_{x \to 0} \frac{(1+x)^{1/3} (\sqrt{4+x} -1) - \sqrt{1-x}}{4 x}$
• June 6th 2010, 05:09 AM
skeeter
Quote:

Originally Posted by bgbgbgbg
$lim_(x->0) ((1+x)^(1/3) (sqrt(4+x)-1)-sqrt(1-x))/(4 x$)

is this what you mean?

$\lim_{x \to 0} \frac{(1+x)^{\frac{1}{3}} [(\sqrt{4+x}-1)-\sqrt{1-x}]}{4x}$
• June 6th 2010, 06:39 AM
Soroban
Hello, bgbgbgbg!

I think you meant: . $\lim_{x\to0} \frac{(1+x)^{1/3} (\sqrt{4+x}-1)-\sqrt{1-x}}{4x}$

. . But it doesn't matter . . .

Plug in $x = 0$ and see what you get.