Hi everyone,
I have a simple question but I can't solve it
what is the intersection point between these two parabola
$\displaystyle y=x^2$
and
$\displaystyle x=4y-y^2$
Hi everyone,
I have a simple question but I can't solve it
what is the intersection point between these two parabola
$\displaystyle y=x^2$
and
$\displaystyle x=4y-y^2$
when I expand the equation $\displaystyle y=(4y-y^2)^2$
it will be
$\displaystyle y^4-8y^3+16y^2-y=0$
I know that $\displaystyle y=0$
but what about the other solution of the equation?
when I expand the equation $\displaystyle y=(4y-y^2)^2$
it will be
$\displaystyle y^4-8y^3+16y^2-y=0$
I know that $\displaystyle y=0$
but what about the other solution of the equation?
I know the meaning of intermediate value theorem is that there is apoint c in interval $\displaystyle [a,b]$ for a function f verifying
$\displaystyle f'(c)=(f(b)-f(a))/(b-a)$
How is this related to the solution of the equation?
I know the meaning of intermediate value theorem is that there is apoint c in interval $\displaystyle [a,b]$ for a function f verifying
$\displaystyle f'(c)=(f(b)-f(a))/(b-a)$
How is this related to the solution of the equation?