I'm having difficulty working with complex numbers. In rectangular and polar forms.
I have:
$\displaystyle 1,94 - j0,43 = \frac{1}{\frac{1}{X} + \frac{1}{2-j2} + \frac{1}{10 +j0}}$
How can I calculate X in rectangular or polar?
The basic algebraic manipulation required to solve this equation is no different to what you would need for an equation with real number.
Clearly you will want to reciprocate something. so polar form of a complex number is handy because for $\displaystyle z = R e^{i \theta} \ \ \ \frac{1}{z} = R^{-1} e^{-i \theta} $
Post again if you are still having troubles.
Bobak
In some countries, a comma is used for a decimal point. Also, in electrical engineering, the symbol $\displaystyle j$ is used for $\displaystyle \sqrt{-1}$ to avoid ambiguity ($\displaystyle i$ is used for something else).
I assume this is actually
$\displaystyle 1.94 + 0.43j = \frac{1}{\frac{1}{X} + \frac{1}{2 - 2j} + \frac{1}{10 + 0j}}$.
Strange as it may seem but I know that backwards and forwards anagramatised.
That only slightly helps, but it does not tell me what the OP intended but only your guess, well I can guess myself but refuse to.I assume this is actually
$\displaystyle 1.94 + 0.43j = \frac{1}{\frac{1}{X} + \frac{1}{2 - 2j} + \frac{1}{10 + 0j}}$.
CB
Strange as it may seem but I know that forwards and backwards anagrammatised.
That only slightly helps since but it does not tell me what the OP intended but only your guess, well I can guess myself but refuse to.I assume this is actually
$\displaystyle 1.94 + 0.43j = \frac{1}{\frac{1}{X} + \frac{1}{2 - 2j} + \frac{1}{10 + 0j}}$.
My request that the OP clarifies what they mean is for their benefit not mine. It is important that people learn to express themselves clearly without ambiguity (unless intended)
CB