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**Savior_Self** Simplify: $\displaystyle \cot(-x) (\cos x) (\tan^2 x + 1)$

I'll show you what I have so far. My problem is I don't really know when I'm finished.

$\displaystyle \cot(-x) (\cos x) (\tan^2 x + 1)$

$\displaystyle (\frac{1}{-\tan x)})(\frac{1}{\sec x})(\sec^2 x)$

$\displaystyle (\frac{1}{-\tan x})(\sec x)$

$\displaystyle (\frac{-\sin x}{\cos x})(\frac{1}{\cos x})$ NO!!!

and I have my final answer as $\displaystyle \frac{-\sin x}{\cos^2 x}$

Is this where I should end it, or should I keep going?

Thanks.