1. g(f(x)) problem.

For all nonzero numbers, if f(x)= x^2 - 1/ x^2 + 1 and g(x)= 1/ x^2, then g(f(x))=

2. Originally Posted by dnntau
For all nonzero numbers, if f(x)= x^2 - 1/ x^2 + 1 and g(x)= 1/ x^2, then g(f(x))=

$f(x) = x^2 - \frac{1}{x^2}$

$g(x) = \frac{1}{x^2}$

just sub f(x) instead of x

$g(f(x)) = \frac{1}{(f(x))^2}$

3. Thank you.