find the vertex, focus, and directrix of the parabola and sketch its graph
x + y^2 = 0
as mentioned since $\displaystyle h=0$ and $\displaystyle k=0 $
then you have a vertex at $\displaystyle V(0.0)$
so now we have the equation of $\displaystyle y^2 = 4ax$ here $\displaystyle 4a= -1$ so $\displaystyle a = -\frac{1}{4}$
Focus at $\displaystyle (a,0)$ so $\displaystyle F(-\frac{1}{4},0)$
Directix at $\displaystyle x = -a$ so $\displaystyle x =\frac{1}{4}$ is the Directix
note some books use $\displaystyle a$ versus $\displaystyle p$ as the variable