Log(base a)2=x Log(base a)5=y find log(base 2)5? How would you do this?
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Originally Posted by p4pri Log(base a)2=x Log(base a)5=y find log(base 2)5? How would you do this? Use the change of base rule: $\displaystyle \log_b(a) = \frac{\log_c(a)}{\log_c(b)}$ You should find that a cancels As an example $\displaystyle x = \log_a(2) = \frac{\log_2(2)}{\log_2(a)} = \frac{1}{\log_2(a)}$
Therefore, from what p4pri has said, log(base 2) 5 = (log(base a)5)/(log(base a)2) = y/x
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