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Last edited by eichyess; May 26th 2010 at 10:04 PM.
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Do you mean $\displaystyle y=\frac{x^2-4}{x^2-9}$ ??
yeah
$\displaystyle y=\frac{x^2-4}{x^2-9}=\frac{x^2-4}{(x-3)(x+3)}$ What are the vertical asymptotes?
i dont know?
Originally Posted by eichyess i dont know? Last hint: $\displaystyle (x-3)(x+3)\neq 0$
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