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- May 26th 2010, 06:49 PMeichyessintercepts and asymptotes
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- May 26th 2010, 07:12 PMpickslides
Do you mean $\displaystyle y=\frac{x^2-4}{x^2-9}$ ??

- May 26th 2010, 07:18 PMeichyess
yeah

- May 26th 2010, 09:08 PMpickslides
$\displaystyle y=\frac{x^2-4}{x^2-9}=\frac{x^2-4}{(x-3)(x+3)}$

What are the vertical asymptotes? - May 26th 2010, 09:34 PMeichyess
i dont know?

- May 26th 2010, 09:36 PMpickslides