1. Is this right?

Question: If the equation x^2 + y^2 = 36 is changed to x^2 + (y+3)^2 = 36, what effect will this have on the graph.

I think that it will slide it 3 units up, but I'm not a hundred percent sure.

2. Originally Posted by iluvmathbutitshard
Question: If the equation x^2 + y^2 = 36 is changed to x^2 + (y+3)^2 = 36, what effect will this have on the graph.

I think that it will slide it 3 units up, but I'm not a hundred percent sure.
The center changes from $(0,0)$ to $(0,-3)$.
So?

3. So three units down?

4. Originally Posted by iluvmathbutitshard
So three units down?
It would seem so.

5. Originally Posted by iluvmathbutitshard
Question: If the equation x^2 + y^2 = 36 is changed to x^2 + (y+3)^2 = 36, what effect will this have on the graph.

I think that it will slide it 3 units up, but I'm not a hundred percent sure.
Your own subconscious mind was correcting you.
You may luv maths but it's hard if the conscious does all the work.

Basically, the equation of a circle is Pythagoras' theorem applied to
all points on the circumference and the centre.

The distance formula is also Pythagoras' theorem

$\left(x-x_c\right)^2+\left(y-y_c\right)^2=r^2$

where $\left(x_c,\ y_c\right)$ are the x and y co-ordinates of the circle centre.

$x^2+(y+3)^2=36$

$[x-(0)]^2+[y-(-3)]^2=6^2$