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Math Help - Is this right?

  1. #1
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    Is this right?

    Question: If the equation x^2 + y^2 = 36 is changed to x^2 + (y+3)^2 = 36, what effect will this have on the graph.

    I think that it will slide it 3 units up, but I'm not a hundred percent sure.
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  2. #2
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    Quote Originally Posted by iluvmathbutitshard View Post
    Question: If the equation x^2 + y^2 = 36 is changed to x^2 + (y+3)^2 = 36, what effect will this have on the graph.

    I think that it will slide it 3 units up, but I'm not a hundred percent sure.
    The center changes from (0,0) to (0,-3).
    So?
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  3. #3
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    So three units down?
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  4. #4
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    Quote Originally Posted by iluvmathbutitshard View Post
    So three units down?
    It would seem so.
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    Quote Originally Posted by iluvmathbutitshard View Post
    Question: If the equation x^2 + y^2 = 36 is changed to x^2 + (y+3)^2 = 36, what effect will this have on the graph.

    I think that it will slide it 3 units up, but I'm not a hundred percent sure.
    Your own subconscious mind was correcting you.
    You may luv maths but it's hard if the conscious does all the work.

    Basically, the equation of a circle is Pythagoras' theorem applied to
    all points on the circumference and the centre.

    The distance formula is also Pythagoras' theorem

    \left(x-x_c\right)^2+\left(y-y_c\right)^2=r^2

    where \left(x_c,\ y_c\right) are the x and y co-ordinates of the circle centre.

    x^2+(y+3)^2=36

    [x-(0)]^2+[y-(-3)]^2=6^2
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