Hello guys.
I know this must be pretty basic. But, I don't get it.
How do I solve 0,6 = 0,95^x ?
This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated.
1. Use logarithms:
$\displaystyle 0,6 = 0,95^x~\implies~x=\log_{0.95}(0.6)$
2. Now use the base-change-formula:
$\displaystyle x=\log_{0.95}(0.6)~\implies~x=\frac{\ln(0.6)}{\ln( 0.95)}$
3. Hint: Better use a decimal point to separate the integer part from the fraction part of a number.