Hello guys.

I know this must be pretty basic. But, I don't get it.

How do I solve 0,6 = 0,95^x ?

This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated.

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- May 23rd 2010, 09:26 AMAlvyEquation - Exponential Function
Hello guys.

I know this must be pretty basic. But, I don't get it.

How do I solve 0,6 = 0,95^x ?

This is from an equation. I got up to this point, but I can't finish it. Any help would be appreciated. - May 23rd 2010, 10:33 AMearboth
1. Use logarithms:

$\displaystyle 0,6 = 0,95^x~\implies~x=\log_{0.95}(0.6)$

2. Now use the base-change-formula:

$\displaystyle x=\log_{0.95}(0.6)~\implies~x=\frac{\ln(0.6)}{\ln( 0.95)}$

3. Hint: Better use a decimal point to separate the integer part from the fraction part of a number. - May 23rd 2010, 10:33 AMe^(i*pi)