If f(x) = sqrt(x+4), use a calculator to compute [f(4+h)-f(2)]/h for h = ±0.1, ±0.05 So do I just put f(x) in place of the f's when putting into my calculator and do the negative and positive for each ± correct?
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Originally Posted by brumby_3 If f(x) = sqrt(x+4), use a calculator to compute [f(4+h)-f(2)]/h for h = ±0.1, ±0.05 So do I just put f(x) in place of the f's when putting into my calculator and do the negative and positive for each ± correct? $\displaystyle \frac{f(4+h)-f(2)}{h}=\frac{\sqrt{(4+h)+4}-\sqrt{2+4}}{h}$
So I need to plug the negative and positive of each number into the function to get the answer?
Yep, four problems to complete.
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