If f(x) = sqrt(x+4), use a calculator to compute [f(4+h)-f(2)]/h for h =
±0.1, ±0.05

So do I just put f(x) in place of the f's when putting into my calculator and do the negative and positive for each ± correct?

2. Originally Posted by brumby_3
If f(x) = sqrt(x+4), use a calculator to compute [f(4+h)-f(2)]/h for h =
±0.1, ±0.05

So do I just put f(x) in place of the f's when putting into my calculator and do the negative and positive for each ± correct?
$\frac{f(4+h)-f(2)}{h}=\frac{\sqrt{(4+h)+4}-\sqrt{2+4}}{h}$

3. So I need to plug the negative and positive of each number into the function to get the answer?

4. Yep, four problems to complete.