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Math Help - Simple question about graphing a parabola with titled axis

  1. #1
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    Question Simple question about graphing a parabola with titled axis

    The equation for the parabola is

    x^2-2xy+y^2-2sqrt(2)x-2sqrt(2)y=0

    I know I have to use cot2θ= (A-C)/B

    But then I get cot2θ= (1-1)/-2 = 0

    I know what to do if I got an actual value, but I'm stuck since it's 0.

    I would really appreciate any help.
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  2. #2
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    Quote Originally Posted by Eric21 View Post
    The equation for the parabola is

    x^2-2xy+y^2-2sqrt(2)x-2sqrt(2)y=0

    I know I have to use cot2θ= (A-C)/B

    But then I get cot2θ= (1-1)/-2 = 0

    I know what to do if I got an actual value, but I'm stuck since it's 0.

    I would really appreciate any help.
    \cot (2 \theta) = 0 \Rightarrow 2 \theta = \frac{\pi}{2}.
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