Thread: help with these inequalities

1.x+3/2x>1
2.4/x+1<3/1
3.3/x-2≤1

i know theres a method for this to find 2 solutions but i dont remember it can someone please help

Originally Posted by andy69

1.x+3/2x>1
2.4/x+1<3/1
3.3/x-2≤1

i know theres a method for this to find 2 solutions but i dont remember it can someone please help

What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it $\displaystyle \frac{x + 3}{2x} > 1$ or $\displaystyle x + \frac{3}{x} > 1$?

Is Q2 $\displaystyle \frac{4}{x + 1} < \frac{3}{1}$ or $\displaystyle \frac{4}{x} + 1 < \frac{3}{1}$?

Is Q3 $\displaystyle \frac{3}{x - 2} \leq 1$ or $\displaystyle \frac{3}{x} - 2 \leq 1$?

Originally Posted by Prove It

What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it $\displaystyle \frac{x + 3}{2x} > 1$ or $\displaystyle x + \frac{3}{x} > 1$?

Is Q2 $\displaystyle \frac{4}{x + 1} < \frac{3}{1}$ or $\displaystyle \frac{4}{x} + 1 < \frac{3}{1}$?

Is Q3 $\displaystyle \frac{3}{x - 2} \leq 1$ or $\displaystyle \frac{3}{x} - 2 \leq 1$?

or (question 1)


(question 2)


(question 3)

sorry im new to this site im just getting use to it those are the questions

Originally Posted by Prove It

What you have written is extremely confusing... Please use brackets where they're needed.

I.e. in Q1 is it $\displaystyle \frac{x + 3}{2x} > 1$ or $\displaystyle x + \frac{3}{x} > 1$?

Is Q2 $\displaystyle \frac{4}{x + 1} < \frac{3}{1}$ or $\displaystyle \frac{4}{x} + 1 < \frac{3}{1}$?

Is Q3 $\displaystyle \frac{3}{x - 2} \leq 1$ or $\displaystyle \frac{3}{x} - 2 \leq 1$?

this is question 1 sorry