how to integrate y=(1+sin2x)/(cosx+sinx)between x=0 and x=45(in degrees)
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Originally Posted by prasum how to integrate y=(1+sin2x)/(cosx+sinx)between x=0 and x=45(in degrees) Prove the following identity: $\displaystyle \frac{1 + \sin (2x)}{\cos (x) + \sin (x)} = \cos (x) + \sin (x)$. Now the integration is trivial.
thanks for the suggestion. please tell me how to prove the identity
Originally Posted by prasum thanks for the suggestion. please tell me how to prove the identity $\displaystyle \frac{1+sin(2x)}{cosx+sinx} \times \frac{cosx+sinx}{cosx+sinx}$ Now simplify. I hope you know that sin2x = 2sinx.cosx
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