9 = 40(2)^2x+1

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- May 17th 2010, 07:10 PMadvancedfunctions2010Solve for X
9 = 40(2)^2x+1

- May 17th 2010, 07:36 PMharish21
- May 17th 2010, 08:04 PMAllanCuz
I think he wants,

$\displaystyle 9 = 40(2)^{2x+1 } $

In which case we use basic logs.

$\displaystyle ln ( \frac{ 9}{40} ) = ln (2^{2x+1}) = (2x+1) ln2 $

$\displaystyle \frac { ln ( \frac{ 9}{40} ) }{ ln2} = 2x + 1 $

$\displaystyle \frac { ln ( \frac{ 9}{40} ) }{2 ln2} - \frac{1}{2} = x $